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10r-r^2=25
We move all terms to the left:
10r-r^2-(25)=0
We add all the numbers together, and all the variables
-1r^2+10r-25=0
a = -1; b = 10; c = -25;
Δ = b2-4ac
Δ = 102-4·(-1)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$r=\frac{-b}{2a}=\frac{-10}{-2}=+5$
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